dek1PZ

Written on June 24, 2019
% Dans le préambule
% -----------------
\usepackage{amsmath}
% -----------------

\begin{align*}
\int_0^1\sqrt{1-x^2}dx
   &=\int_0^\frac{\pi}{2}
         \sqrt{1-\sin^2t}\cos t dt\\
   &=\int_0^\frac{\pi}{2}
         \frac{1+\cos 2t}{2}dt\\
   &=\frac{\pi}{4}
\end{align*}