dek1PZ
Written on June 24, 2019
% Dans le préambule
% -----------------
\usepackage{amsmath}
% -----------------
\begin{align*}
\int_0^1\sqrt{1-x^2}dx
&=\int_0^\frac{\pi}{2}
\sqrt{1-\sin^2t}\cos t dt\\
&=\int_0^\frac{\pi}{2}
\frac{1+\cos 2t}{2}dt\\
&=\frac{\pi}{4}
\end{align*}